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In $\triangle ABC, \angle B = 90^\circ$. If $\frac{AB}{AC} = \frac{1}{2}$, then $\cos C$ is equal to
- (a)$\frac{3}{2}$
- (b)$\frac{1}{2}$
- (c)$\frac{\sqrt{3}}{2}$
- (d)$\frac{1}{\sqrt{3}}$
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Ans: (C) $\frac{\sqrt{3}}{2}$
In △ ABC, ∠ B = 90° . If AB/AC = 1/2 , then C is equal to
CBSE Class 10 Maths PYQ · Trigonometry · Find T-ratio or value of Expression · 1 Mark · March 2025 · Basic
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