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If $\tan \theta = \frac{x}{y}$, then $\cos \theta$ is equal to
- (a)$\frac{x}{\sqrt{x^2 + y^2}}$
- (b)$\frac{y}{\sqrt{x^2 + y^2}}$
- (c)$\frac{x}{\sqrt{x^2-y^2}}$
- (d)$\frac{y}{\sqrt{x^2-y^2}}$
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(B) $\frac{y}{\sqrt{x^2 + y^2}}$