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If $\sin \theta = \frac{1}{9}$, then $\tan \theta$ is equal to
- (a)$\frac{1}{4\sqrt{5}}$
- (b)$\frac{4\sqrt{5}}{9}$
- (c)$\frac{1}{8}$
- (d)$4\sqrt{5}$
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Ans: (A) $\frac{1}{4\sqrt{5}}$
If θ = 1/9 , then θ is equal to
CBSE Class 10 Maths PYQ · Trigonometry · Find T-ratio or value of Expression · 1 Mark · March 2025 · Basic
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