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If $\sin (\alpha + \beta) = 1$, then the value of $\sin \left(\frac{\alpha + \beta}{2}\right)$ is :
- (a)$\frac{1}{\sqrt{2}}$
- (b)$\frac{1}{2}$
- (c)$0$
- (d)$1$
Show SolutionHide Solution↓
(A) $\frac{1}{\sqrt{2}}$
If (α + β) = 1 , then the value of ≤ft(α + β/2 ) is :
CBSE Class 10 Maths PYQ · Trigonometry · Find Angle of T-Ratio · 1 Mark · March 2025 · Standard
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