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If $\sin \theta = \cos \theta$, ($0^\circ < \theta < 90^\circ$), then value of $(\sec \theta \sin \theta)$ is :
- (a)$\frac{1}{\sqrt{2}}$
- (b)$1$
- (c)$\sqrt{2}$
- (d)$0$
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(C) $1$
CBSE Class 10 Maths PYQ · Trigonometry · Find Angle of T-Ratio · 1 Mark · March 2024 · Standard
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