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If $\sin \theta = \cos \theta$ ($0^\circ < \theta < 90^\circ$), then the value of $\sec \theta \cdot \sin \theta$ is:
- (a)$\frac{1}{\sqrt{2}}$
- (b)$\sqrt{2}$
- (c)$0$
- (d)$1$
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(D) $1$
If θ = θ ( 0° < θ < 90° ), then the value of θ · θ is:
CBSE Class 10 Maths PYQ · Trigonometry · Find Angle of T-Ratio · 1 Mark · March 2025 · Standard
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