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From the given figure, find the value of $\sin \alpha$.
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$\sin \alpha = \frac{\text{Perpendicular}}{\text{Hypotenuse}}$
$\sin \alpha = \frac{6}{3+9} = \frac{6}{12} = \frac{1}{2}$
$\sin \alpha = \frac{6}{3+9} = \frac{6}{12} = \frac{1}{2}$