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If $\sin A = \frac{3}{5}$ and $\cos B = \frac{12}{13}$, then find the value of $(\tan A + \tan B)$.
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$$\begin{aligned}& \sin A = \frac{3}{5} \Rightarrow \tan A = \frac{3}{4} \\ & \cos B = \frac{12}{13} \Rightarrow \tan B = \frac{5}{12} \\ & \tan A + \tan B = \frac{3}{4} + \frac{5}{12} = \frac{14}{12}\end{aligned}$$ or $\frac{7}{6}$