20
If $\sin A = y$, then express $\cos A$ and $\tan A$ in terms of $y$.
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$\cos A = \sqrt{1-\sin^2 A} = \sqrt{1-y^2}$
$\tan A = \frac{\sin A}{\cos A} = \frac{y}{\sqrt{1-y^2}}$
$\tan A = \frac{\sin A}{\cos A} = \frac{y}{\sqrt{1-y^2}}$