21
For an acute angle $\theta$, if $\cos \theta = \frac{8}{17}$, then $\frac{8 \sec \theta + 1}{8 \sec \theta - 1}$ equals
- (a)$\frac{64}{63}$
- (b)$0$
- (c)$\frac{65}{63}$
- (d)$1$
Show SolutionHide Solution↓
Sol. (C) $\frac{65}{63}$
For an acute angle θ , if θ = 8/17 , then 8 θ + 1/8 θ - 1 equals
CBSE Class 10 Maths PYQ · Trigonometry · Find T-ratio or value of Expression · 1 Mark · March 2026 · Standard
Solve it yourself first — then press ↓ or tap Show Solution. Use ← → for previous / next question.