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For an acute angle $\theta$, if $\sin \theta = \frac{1}{9}$, then value of $\frac{9 \cosec \theta+1}{9 \cosec \theta-1}$ is
- (a)$0$
- (b)$\frac{80}{81}$
- (c)$1$
- (d)$\frac{82}{80}$
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Sol. (D) $\frac{82}{80}$ (1 Mark)
For an acute angle θ , if θ = 1/9 , then value of 9 θ+1/9 θ-1 is
CBSE Class 10 Maths PYQ · Trigonometry · Find T-ratio or value of Expression · 1 Mark · March 2026 · Standard
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