72
In the given figure, $\frac{EA}{EC} = \frac{EB}{ED}$, prove that $\triangle EAB \sim \triangle ECD$

Show SolutionHide Solution↓
In $\triangle EAB$ and $\triangle ECD$
$\frac{EA}{EC} = \frac{EB}{ED}$
$\angle AEB = \angle CED$
$\triangle EAB \sim \triangle ECD$
$\frac{EA}{EC} = \frac{EB}{ED}$
$\angle AEB = \angle CED$
$\triangle EAB \sim \triangle ECD$