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In the given figure, $\triangle AHK \sim \triangle ABC$. If $AK = 8$ cm, $BC = 3.2$ cm and $HK = 6.4$ cm, then find the length of $AC$.
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$\therefore \triangle AHK \sim \triangle ABC$ (given)
$$\begin{aligned}& \therefore \frac{HK}{BC} = \frac{AK}{AC} \\ & \Rightarrow \frac{6.4}{3.2} = \frac{8.0}{AC} \\ & AC = 4 \text{ cm}\end{aligned}$$
$$\begin{aligned}& \therefore \frac{HK}{BC} = \frac{AK}{AC} \\ & \Rightarrow \frac{6.4}{3.2} = \frac{8.0}{AC} \\ & AC = 4 \text{ cm}\end{aligned}$$