71
In $\triangle ABC$, altitudes AD and BE are drawn. If AD = 7 cm, BE = 9 cm and EC = 12 cm then, find the length of CD.
Show SolutionHide Solution↓
$\triangle BEC \sim \triangle ADC$
$\Rightarrow \frac{BE}{AD} = \frac{EC}{CD}$
$\Rightarrow CD = \frac{12\times7}{9} = \frac{28}{3} \text{ or } 9.33 \text{ cm}$
$\Rightarrow \frac{BE}{AD} = \frac{EC}{CD}$
$\Rightarrow CD = \frac{12\times7}{9} = \frac{28}{3} \text{ or } 9.33 \text{ cm}$