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In the given figure $\triangle ABC$ is shown. $DE$ is parallel to $BC$. If $AD = 5$ cm, $DB = 2.5$ cm and $BC = 12$ cm, then $DE$ is equal to

- (a)$10$ cm
- (b)$6$ cm
- (c)$8$ cm
- (d)$7.5$ cm
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(C) $8$ cm
CBSE Class 10 Maths PYQ · Triangles · BPT & Converse · 1 Mark · March 2024 · Standard
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