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In the given figure $\Delta ABC$ is shown. DE is parallel to BC. If AD = $5$ cm, DB = $2.5$ cm and BC = $12$ cm, then DE is equal to

- (a)$10$ cm
- (b)$8$ cm
- (c)$6$ cm
- (d)$7.5$ cm
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(C) $8$ cm
CBSE Class 10 Maths PYQ · Triangles · BPT & Converse · 1 Mark · March 2024 · Standard
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