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In a $\triangle ABC$, a line DE is drawn parallel to BC to intersect AB at D and AC at E. If AD = $2$ cm, BD = $3$ cm and DE = $4$ cm, then the length of BC (in cm) is :
- (a)$6$
- (b)$10$
- (c)$\frac{8}{3}$
- (d)$\frac{20}{3}$
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Sol. (B) $10$