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In the given figure, in $\triangle ABC$, $DE \parallel BC$. If $AD = 2.4 \text{ cm}$, $DB = 4 \text{ cm}$ and $AE = 2 \text{ cm}$, then the length of $AC$ is :

- (a)$\frac{10}{3} \text{ cm}$
- (b)$\frac{3}{10} \text{ cm}$
- (c)$\frac{16}{3} \text{ cm}$
- (d)$1.2 \text{ cm}$
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(C) $\frac{16}{3} \text{ cm}$