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In the adjoining figure, $VW \parallel YZ$, $XV = \frac{3}{2} VY$ and $WX = 4$ cm. Find the length of $XZ$.
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Ans. As $VW \parallel YZ$,
$\frac{XV}{VY} = \frac{XW}{WZ}$ (1/2 Mark)
$\frac{3}{2} = \frac{4}{WZ}$ (1/2 Mark)
$WZ = \frac{8}{3}$ (1/2 Mark)
$XZ = 4 + \frac{8}{3} = \frac{20}{3}$ cm (1/2 Mark)
$\frac{XV}{VY} = \frac{XW}{WZ}$ (1/2 Mark)
$\frac{3}{2} = \frac{4}{WZ}$ (1/2 Mark)
$WZ = \frac{8}{3}$ (1/2 Mark)
$XZ = 4 + \frac{8}{3} = \frac{20}{3}$ cm (1/2 Mark)