50
In the adjoining figure,
$AP = \frac{1}{2} AB$ and $PQ \parallel BC$.
If $CQ = 3$ cm, then find the length of $AC$.
$AP = \frac{1}{2} AB$ and $PQ \parallel BC$.
If $CQ = 3$ cm, then find the length of $AC$.
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Let $AC = x$ cm
$\frac{AP}{AB} = \frac{AQ}{AC} = \frac{1}{2}$ (1 Mark)
$\frac{x-3}{x} = \frac{1}{2}$ (1/2 Mark)
$x = 6 \implies AC = 6$ cm (1/2 Mark)
$\frac{AP}{AB} = \frac{AQ}{AC} = \frac{1}{2}$ (1 Mark)
$\frac{x-3}{x} = \frac{1}{2}$ (1/2 Mark)
$x = 6 \implies AC = 6$ cm (1/2 Mark)