52
In the given figure, QR $||$ CB and RP $||$ AC. If BR = 10 cm, QA = 12 cm, BP = 12 cm and PC = 18 cm, then find the lengths of AR and QC.
Show SolutionHide Solution↓
Solution: $PR|| CA \therefore \frac{BP}{PC} = \frac{BR}{RA} \Rightarrow \frac{12}{18} = \frac{10}{AR} \Rightarrow AR = 15$ cm (1 Mark)
$QR|| CB \therefore \frac{AR}{RB} = \frac{AQ}{QC} \Rightarrow \frac{15}{10} = \frac{12}{QC} \Rightarrow QC = 8$ cm (1 Mark)
$QR|| CB \therefore \frac{AR}{RB} = \frac{AQ}{QC} \Rightarrow \frac{15}{10} = \frac{12}{QC} \Rightarrow QC = 8$ cm (1 Mark)