99
Verify the relationship between the zeroes and the coefficients of the quadratic polynomial $25x^2 - 16$.
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Solution: Zeroes of $25x^2 - 16$ are $\frac{4}{5}, -\frac{4}{5}$ (1 Mark)
Sum of zeroes $= \frac{4}{5} + (-\frac{4}{5}) = 0 = \frac{-0}{25} = \frac{\text{-Coefficient of } x}{\text{Coefficient of } x^2}$ (1/2 Mark)
Product of zeroes $= \frac{4}{5} \times -\frac{4}{5} = -\frac{16}{25} = \frac{\text{Constant term}}{\text{Coefficient of } x^2}$ (1/2 Mark)
Sum of zeroes $= \frac{4}{5} + (-\frac{4}{5}) = 0 = \frac{-0}{25} = \frac{\text{-Coefficient of } x}{\text{Coefficient of } x^2}$ (1/2 Mark)
Product of zeroes $= \frac{4}{5} \times -\frac{4}{5} = -\frac{16}{25} = \frac{\text{Constant term}}{\text{Coefficient of } x^2}$ (1/2 Mark)