98
Verify the relation between the zeroes and the coefficients of the quadratic polynomial $4x^2 – 9$.
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Solution: Zeroes of $4x^2 – 9$ are $\frac{3}{2}, -\frac{3}{2}$ (1 Mark)
Sum of zeroes = $\frac{3}{2} + (-\frac{3}{2}) = 0 = -\frac{\text{Coefficient of x}}{\text{Coefficient of x}^2}$ (1/2 Mark)
Product of zeroes = $\frac{3}{2} \times (-\frac{3}{2}) = -\frac{9}{4} = \frac{\text{Constant term}}{\text{Coefficient of x}^2}$ (1/2 Mark)
Sum of zeroes = $\frac{3}{2} + (-\frac{3}{2}) = 0 = -\frac{\text{Coefficient of x}}{\text{Coefficient of x}^2}$ (1/2 Mark)
Product of zeroes = $\frac{3}{2} \times (-\frac{3}{2}) = -\frac{9}{4} = \frac{\text{Constant term}}{\text{Coefficient of x}^2}$ (1/2 Mark)