100
Verify the relationship between the zeroes and the coefficients of the quadratic polynomial $9x^2 - 25$.
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Getting zeroes: $\frac{-5}{3}$ and $\frac{5}{3}$ (1/2+1/2 Mark)
nSum of zeroes = $\frac{-5}{3} + \frac{5}{3} = 0 = \frac{-0}{9} = \frac{-\text{Coefficient of } x}{\text{Coefficient of } x^2}$ (1/2 Mark)
nProduct of zeroes = $\frac{-5}{3} \times \frac{5}{3} = \frac{-25}{9} = \frac{\text{Constant term}}{\text{Coefficient of } x^2}$ (1/2 Mark)
nSum of zeroes = $\frac{-5}{3} + \frac{5}{3} = 0 = \frac{-0}{9} = \frac{-\text{Coefficient of } x}{\text{Coefficient of } x^2}$ (1/2 Mark)
nProduct of zeroes = $\frac{-5}{3} \times \frac{5}{3} = \frac{-25}{9} = \frac{\text{Constant term}}{\text{Coefficient of } x^2}$ (1/2 Mark)