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If one zero of the polynomial $x^2-5x-c$ is $(-1)$, find the value of $c$. Also, find the other zero.
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As $-1$ is the zero, so $1 + 5 - c = 0$ gives $c = 6$ (1 Mark)
Sum of zeroes = $5$ (1/2 Mark)
Thus, other zero is $6$ (1/2 Mark)
Sum of zeroes = $5$ (1/2 Mark)
Thus, other zero is $6$ (1/2 Mark)