97
The two angles of a right angled triangle other than $90^{\circ}$ are in the ratio $2:3$. Express the given situation algebraically as a system of linear equations in two variables and hence solve it.
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Let the measures of two angles be $x$ and $y$
$ATQ$
$x + y = 90^{\circ} \dots (i)$
and $\frac{x}{y} = \frac{2}{3} \implies 3x - 2y = 0 \dots (ii)$
Solving (i) and (ii), we get $x = 36^{\circ}, y = 54^{\circ}$
$ATQ$
$x + y = 90^{\circ} \dots (i)$
and $\frac{x}{y} = \frac{2}{3} \implies 3x - 2y = 0 \dots (ii)$
Solving (i) and (ii), we get $x = 36^{\circ}, y = 54^{\circ}$