98
The perimeter of a rectangle is $70$ cm. The length of the rectangle is $5$ cm more than twice is breadth. Express the given situation as a system of linear equations in two variables and hence solve it.
Show SolutionHide Solution↓
Let the length and breadth of rectangle be $x$ and $y$ respectively. ATQ $x + y = 35 \dots (i)$ and $x - 2y = 5 \dots (ii)$. Solving (i) and (ii), we get $x = 25$ and $y = 10$. Hence the length and breadth of rectangle are $25$ cm and $10$ cm respectively.