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3 chairs and 1 table cost ₹900; whereas 5 chairs and 3 tables cost ₹2,100. If the cost of 1 chair is $x$ and the cost of 1 table is $y$, then the situation can be represented algebraically as
- (a)$3x + y = 900, 3x + 5y = 2100$
- (b)$x + 3y = 900, 3x + 5y = 2100$
- (c)$3x + y = 900, 5x + 3y = 2100$
- (d)$x + 3y = 900, 5x + 3y = 2100$
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(C) $3x + y = 900, 5x + 3y = 2100$