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The perimeter of a rectangle is $70$ cm. The length of the rectangle is $5$ cm more than twice is breadth. Express the given situation as a system of linear equations in two variables and hence solve it.
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Let the length and breadth of rectangle be $x$ and $y$ respectively.
ATQ
$x + y = 35 \dots (i)$
and $x - 2y = 5 \dots (ii)$.
Solving (i) and (ii), we get $x = 25$ and $y = 10$.
Hence the length and breadth of rectangle are $25$ cm and $10$ cm respectively.
ATQ
$x + y = 35 \dots (i)$
and $x - 2y = 5 \dots (ii)$.
Solving (i) and (ii), we get $x = 25$ and $y = 10$.
Hence the length and breadth of rectangle are $25$ cm and $10$ cm respectively.