The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60° and the…

1 for correct figure
$PQ = \text{height of } 1^{st} \text{ tower} = 30 \text{ m}$
$AB = \text{height of } 2^{nd} \text{ tower} = h \text{ (say)}$
$\angle PAQ = 60^\circ$, $\angle APB = 30^\circ$
Let $AP = x$
In $\triangle APQ$, $\tan 60^\circ = \frac{PQ}{AP} = \frac{30}{x}$
$\Rightarrow x = \frac{30}{\tan 60^\circ} = \frac{30}{\sqrt{3}} = 10\sqrt{3}$
$\therefore \text{Distance between two towers} = 10\sqrt{3} \text{ m}$
In $\triangle APB$, $\tan 30^\circ = \frac{AB}{AP} = \frac{h}{x}$
$\frac{1}{\sqrt{3}} = \frac{h}{10\sqrt{3}}$
$\Rightarrow h = 10$
$\therefore \text{Height of } 2^{nd} \text{ tower} = 10 \text{ m}$