90
The value of $\sin 90^{\circ} \cos 90^{\circ} - \sin^2 60^{\circ}$ is :
- (a)$\frac{1}{4}$
- (b)$-\frac{3}{4}$
- (c)$\frac{3}{4}$
- (d)$\frac{5}{4}$
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Answer: (C) $-\frac{3}{4}$
CBSE Class 10 Maths PYQ · Trigonometry · Specific Angles Expression · 1 Mark · March 2026 · Basic
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