29
$\frac{5}{8} - \sec^2 60^{\circ} - \tan^2 60^{\circ} + \cos^2 45^{\circ}$ is equal to
- (a)$-\frac{5}{3}$
- (b)$-\frac{1}{2}$
- (c)0
- (d)$-\frac{1}{4}$
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(C) 0
5/8 - 2 60° - 2 60° + 2 45° is equal to
CBSE Class 10 Maths PYQ · Trigonometry · Specific Angles Expression · 1 Mark · March 2023 · Standard
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