6
If $\cos \theta = \frac{x}{y}$, $(x, y \neq 0)$, then $\tan \theta$ is equal to :
- (a)$\frac{y}{\sqrt{y^2 - x^2}}$
- (b)$\frac{\sqrt{y^2 - x^2}}{x}$
- (c)$\frac{x}{\sqrt{x^2 + y^2}}$
- (d)$\frac{x}{\sqrt{y^2 - x^2}}$
Show SolutionHide Solution↓
(C) $\frac{\sqrt{y^2 - x^2}}{x}$