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If $\tan \theta + \frac{1}{\tan \theta} = 2$, find the value of $\tan^2 \theta + \frac{1}{\tan^2\theta}$.
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$(\tan \theta + \frac{1}{\tan \theta})^2 = (2)^2$ (1/2 Mark)
$\tan^2 \theta + \frac{1}{\tan^2 \theta} + 2 = 4$ (1 Mark)
$\Rightarrow \tan^2 \theta + \frac{1}{\tan^2 \theta} = 2$ (1/2 Mark)
$\tan^2 \theta + \frac{1}{\tan^2 \theta} + 2 = 4$ (1 Mark)
$\Rightarrow \tan^2 \theta + \frac{1}{\tan^2 \theta} = 2$ (1/2 Mark)