66
If $\sin \theta = \cos \theta$, ($0^\circ < \theta < 90^\circ$), then value of $(\sec \theta \cdot \sin \theta)$ is :
- (a)$\frac{1}{\sqrt{2}}$
- (b)$\sqrt{2}$
- (c)1
- (d)0
Show SolutionHide Solution↓
(C) 1
If θ = θ , ( 0° < θ < 90° ), then value of ( θ · θ) is : (A) 1√2 (C) 1 (B) √2 (D) 0
CBSE Class 10 Maths PYQ · Trigonometry · Find Angle of T-Ratio · 1 Mark · March 2024 · Standard
Solve it yourself first — then press ↓ or tap Show Solution. Use ← → for previous / next question.