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Given that $\sin \theta = \frac{a}{b}$, then $\cos \theta$ is equal to :
- (a)$\frac{b}{\sqrt{b^2-a^2}}$
- (b)$\frac{b}{a}$
- (c)$\frac{\sqrt{b^2-a^2}}{b}$
- (d)$\frac{a}{\sqrt{b^2-a^2}}$
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(c) $\frac{\sqrt{b^2-a^2}}{b}$ (1 Mark)