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Given that $\sin 2\alpha = \frac{\sqrt{3}}{2}$, the value of $\sin 3\alpha$ is :
- (a)$\frac{3\sqrt{3}}{4}$
- (b)$\frac{1}{2}$
- (c)$1$
- (d)$\frac{\sqrt{3}}{4}$
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(C) $1$ (1 Mark)
Given that 2α = √32 , the value of 3α is :
CBSE Class 10 Maths PYQ · Trigonometry · Specific Angles Expression · 1 Mark · March 2026 · Standard
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