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Evaluate: $\frac{\tan^2 60^\circ + 4 \sin^2 45^\circ + 3 \sec^2 60^\circ + 5 \cos^2 90^\circ}{\text{cosec } 30^\circ + \sec 60^\circ - \cot^2 30^\circ}$
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Sol. $\frac{(\sqrt{3})^2+4(\frac{1}{\sqrt{2}})^2+3(2)^2+5(0)^2}{2+2-(\sqrt{3})^2}$ (3 Marks)
$= \frac{3+2+12+0}{4-3}$ (1 Mark)
$= 17$ (1 Mark)
$= \frac{3+2+12+0}{4-3}$ (1 Mark)
$= 17$ (1 Mark)