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Line $ST$ is drawn parallel to the base $QR$ of a $\Delta PQR$, meeting $PQ$ at $S$ and $PR$ at $T$. If $\frac{PQ}{QS} = 3$ and $TR = 3$ cm, then the length of $PT$ is
- (a)$9$ cm
- (b)$12$ cm
- (c)$6$ cm
- (d)$3$ cm
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Ans: (C) $6$ cm