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In $\triangle ABC, DE || BC$. If $AE = (2x + 1) \text{ cm}, EC = 4 \text{ cm}, AD = (x + 1) \text{ cm}$ and $DB = 3 \text{ cm}$, then value of $x$ is
- (a)$1$
- (b)$\frac{1}{2}$
- (c)$-1$
- (d)$\frac{1}{3}$
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Ans: (B) $\frac{1}{2}$