101
In the given figure, $\triangle AHK \sim \triangle ABC$. If $AK = 10$ cm, $BC = 3.5$ cm and $HK = 7$ cm, find the length of AC.
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$\triangle AHK \sim \triangle ABC$
$\frac{AK}{AC} = \frac{HK}{BC}$ (1 Mark)
$\frac{10}{AC} = \frac{7}{3.5}$ (1/2 Mark)
$\Rightarrow AC = 5$ cm (1/2 Mark)
$\frac{AK}{AC} = \frac{HK}{BC}$ (1 Mark)
$\frac{10}{AC} = \frac{7}{3.5}$ (1/2 Mark)
$\Rightarrow AC = 5$ cm (1/2 Mark)