100
In the figure given above, $\triangle ABC \sim \triangle XYZ$, then find the values of $x$ and $y$.
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$\triangle ABC \sim \triangle XYZ \implies \frac{AB}{XY} = \frac{BC}{YZ} = \frac{AC}{XZ}$ (1 Mark)
$\frac{4}{x} = \frac{6}{7.2} = \frac{y}{6}$ (1/2 Mark + 1/2 Mark)
Solving, we get $x = 4.8$ cm, $y = 5$ cm (1/2 Mark + 1/2 Mark)
$\frac{4}{x} = \frac{6}{7.2} = \frac{y}{6}$ (1/2 Mark + 1/2 Mark)
Solving, we get $x = 4.8$ cm, $y = 5$ cm (1/2 Mark + 1/2 Mark)