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In $\triangle ABC$, P is a point on AB and Q is a point of AC such that PQ $||$ BC. If AP : PB = $3 : 2$, then PQ : BC is equal to :
- (a)$3:2$
- (b)$2:5$
- (c)$3:5$
- (d)$5:3$
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Answer: (C) $3:5$
In △ ABC , P is a point on AB and Q is a point of AC such that PQ || BC. If AP : PB = 3 : 2 , then PQ : BC is equal to :
CBSE Class 10 Maths PYQ · Triangles · BPT & Converse · 1 Mark · March 2026 · Basic
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