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From each end of a solid cylinder of height $20$ cm and base radius $7$ cm, a cone of base radius $2.1$ cm and height $5$ cm is scooped out. Find the volume of the remaining solid.
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Volume of cylinder $= \frac{22}{7} \times 7 \times 7 \times 20 = 3080$ cu. cm
Volume of cones $= 2 \times \frac{1}{3} \times \frac{22}{7} \times \frac{21}{10} \times \frac{21}{10} \times 5 = 46.2$ cu. cm
Volume of remaining solid $= 3080 - 46.2 = 3033.8$ cu. cm
Volume of cones $= 2 \times \frac{1}{3} \times \frac{22}{7} \times \frac{21}{10} \times \frac{21}{10} \times 5 = 46.2$ cu. cm
Volume of remaining solid $= 3080 - 46.2 = 3033.8$ cu. cm