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A hemispherical bowl is made of steel of thickness $1$ cm. The inner radius of the bowl is $5$ cm. The volume of steel used (in cm$^3$) is :
- (a)$182 \pi$
- (b)$\frac{182}{3} \pi$
- (c)$\frac{682}{3} \pi$
- (d)$\frac{364}{3} \pi$
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Ans. (b) $\frac{182}{3} \pi$