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A solid iron pole consists of a solid cylinder of height $200 \text{ cm}$ and base diameter $28 \text{ cm}$, which is surmounted by another cylinder of height $50 \text{ cm}$ and radius $7 \text{ cm}$. Find the mass of the pole, given that $1 \text{ cm}^3$ of iron has approximately $8 \text{ g}$ mass.
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Radius of lower cylinder = $14 \text{ cm}$
Volume of pole = $\frac{22}{7} \times 14 \times 14 \times 200 + \frac{22}{7} \times 7 \times 7 \times 50$
$= 130900 \text{ cm}^3$
Mass of the pole= $8 \times 130900$
$=1047200 \text{ gm}$ or $1047.2 \text{ kg}$
Volume of pole = $\frac{22}{7} \times 14 \times 14 \times 200 + \frac{22}{7} \times 7 \times 7 \times 50$
$= 130900 \text{ cm}^3$
Mass of the pole= $8 \times 130900$
$=1047200 \text{ gm}$ or $1047.2 \text{ kg}$