44
A hemispherical bowl is made of steel of thickness $1$ cm. The outer radius of the bowl is $6$ cm. The volume of steel used (in cm$^3$) is :
- (a)$182 \pi$
- (b)$\frac{182}{3} \pi$
- (c)$\frac{682}{3} \pi$
- (d)$\frac{364}{3} \pi$
Show SolutionHide Solution↓
Sol. (B) $\frac{182}{3} \pi$ (1 Mark)