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Using prime factorisation, find the HCF of 180, 140 and 210.
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$180 = 2^2 \times 3^2 \times 5, 140 = 2^2 \times 5 \times 7, 210 = 2 \times 3 \times 5 \times 7$ ($1\frac{1}{2}$ marks)
$HCF(180, 140, 210) = 2 \times 5 = 10$ ($\frac{1}{2}$ mark)
$HCF(180, 140, 210) = 2 \times 5 = 10$ ($\frac{1}{2}$ mark)