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If $a = 2^4 \times 3^3$, $b = 2^3 \times 3^2 \times 5$, $c = 3^n \times 5^2$ and LCM $(a, b, c) = (5^2 \times 3^4 \times 2^4)$, then $n$ is :
- (a)$1$
- (b)$2$
- (c)$3$
- (d)$4$
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Sol. (D) $4$
CBSE Class 10 Maths PYQ · Real Numbers · Find lcm & hcf · 1 Mark · July 2024 · Standard
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