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If $x = ab^3$ and $y = a^3b$, where $a$ and $b$ are prime numbers, then [HCF $(x, y)$ – LCM $(x, y)$] is equal to :
- (a)$1-ab^3$
- (b)$ab (1-ab)$
- (c)$ab-a^3b^3$
- (d)$ab (1-ab) (1 + ab)$
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(d) $ab(1 - ab)(1 + ab)$
If x = ab3 and y = a3b , where a and b are prime numbers, then [HCF (x, y) – LCM (x, y) ] is equal to :
CBSE Class 10 Maths PYQ · Real Numbers · Find lcm & hcf · 1 Mark · March 2025 · Standard
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